「Java」 parseInt

語法與解析:

static int parseInt(String s)
將字串解析為十進位整數

static int parseInt(String s, int radix)
將字串解析為指定進位的整數

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用法:

public class ParseInt {
    public static void main(String[] args) {
        String s1 = "11";
        int a1 = Integer.parseInt(s1);
        int a2 = Integer.parseInt(s1, 16);
         
        System.out.println(a1); //answer: 11
        System.out.println(a2); //answer: 17

        String s2 = "one";
        int b1 = Integer.parseInt(s1);
        int b2 = Integer.parseInt(s1, 16);
         
        System.out.println(b1); //wrong
        System.out.println(b2); //wrong
    }
}